Question

Two skaters A and B of masses 50kg and 70 kg stand facing each other 6 m apart. Then they pull on a rope stretched between them. How far has each moved when they meet

Answer 1

Here.. Use this pic.. Oooooooookoooooooooooo

Answer 2

Skaters have moved 3.5 m and 2.5 m

Explanation:

Force applied on both skaters should be equal.

So m1s1 = m2s2, where m is mass and s is distance.

Given s1 + s2 = 6 m

Substituting the values, we get 50 * s1 = 70 * s2

50 * s1 = 70 * (6-s1)

s1/6-s1 = 70/50 = 1.4

So the skaters have moved a distance in the ratio 7: 5. Given total distance between the two is 6m, splitting it in the ratio 7:5, we get 3.5 m and 2.5 m respectively.