Physics, asked by aryanaryaman446, 23 days ago

Two skaters weighing in the ratio 3 : 5 and 12 m apart are at rest on a smooth frictionless surface. They pull on a rope stretched between them. The ratio of distance covered by them when they meet each other will be​

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Answered by khakharoshan4
0

Answer:

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Two skaters have weight in the ratio 4:5 and are 9m apart, on a smooth frictionless surface. They pull on a rope stretched between them. The ratio of the distance covered by them when they meet each other will be

A

5:4

B

4:5

C

25:16

D

16:25

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Correct option is A)

Let mass of 2 skaters be 4m and 5m. Let 4m mass move distance x meters and 5m mass moves 9-x distance.

s=ut+

2

1

at

2

x=0+

2

1

4m

F

t

2

9−x=0+

2

1

5m

F

t

2

ratio=

9−x

x

=

2

1

4m

F

t

2

2

1

4m

F

t

2

=5:4

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Answered by sethykhusbu
0

Answer :

Let mass of 2 skaters be 4m and 5m. Let 4m mass move distance x meters and 5m mass moves 9-x distance.

s=ut+

2

1

at

2

x=0+

2

1

4m

F

t

2

9−x=0+

2

1

5m

F

t

2

ratio=

9−x

x

=

2

1

4m

F

t

2

2

1

4m

F

t

2

=5:4

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