Question

Two slips of paper marked 5 and 10 are put in a box and three slips marked 1, 3, 5 are in another. One slip from each box
is drawn.

(a) What is the probability that both show odd number?
(b) What is the probability of getting one odd number and one even number?​

Answer 1

Answer:

the probability that both show odd number is 1/2

the probability of getting one odd number and one even number 1/2

Step-by-step explanation:

Before we answer the question, we need to define probability.

Probability = Favorable outcome/total possible outcomes

Now, we have two boxes. So, we will get the respective probabilities separately first.

Let's call them box A and B respectively.

Box A:

P(Odd number) = 1/2

P(Even number) = 1/2

Box B:

P(Odd number) = 1

P(even number) = 0

Let's answer the questions.

a) P(A is odd) and P(B is odd) = 1/2 × 1 = 1/2

b) P(1 odd number and 1 even number) = P(A is odd and B is even) or P(A is even and B is Odd)

= (1/2 × 0) + (1/2 × 1) = 1/2

Answer 2

Step-by-step explanation:

Given Two slips of paper marked 5 and 10 are put in a box and three slips marked 1, 3, 5 are in another. One slip from each box

is drawn.

a) What is the probability that both show odd number?

(b) What is the probability of getting one odd number and one even number?​

• According to question one box contains (5,10)
• Another box contains (1,3,5)
• Probability for odd number for 1 box = 1/2  
• Probability for odd number for 2 box = 3/3 = 1
• Therefore required probability = 1/2 x 1 = 1/2  
• Now probability of getting one odd and one even
• So P(one odd from 1 box) x P(one even from box 2) + P(one even from box 1) x P(one odd from box 2)
• = 1/2 x 0/3 + 1/2 x 3/3
• = 0 + 1/2  
• = 1/2

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