Question

Two slips of paper marked 5 and 10 are put in a box
and three slips marked 1.3. 5 are in another. One slip
from each box is drawn.
a) What is the probability that both show odá
number?
(b) What is the probability of getting one odd number
and one even number?​

Answer 1

a) Probability that both slips having odd number = $\frac{1}{2}$

b) Probability that slips having one odd number and one even  = $\frac{1}{2}$

Step-by-step explanation:

Two slips of paper are put in a box, the numbers are = 5 and 10

In both slips one is even number and one is odd number.

3 slips of paper are put in another box, the numbers are = 1, 3 and 5

In second box all 3 slips have odd number.

So the sample space are :

(5,1) (5,3) (5,5) (10,1) (10,3) (10,5) = 6 outcomes

(a) Probability that both drawn slips have odd number

    = (5,1) (5,3) (5,5) = $\frac{3}{6}=\frac{1}{2}$

(b) Probability that both drawn slips have one even and one odd number

    = (10,1) (10,3) (10,5) = $\frac{3}{6}=\frac{1}{2}$

a) Probability that both slips having odd number = $\frac{1}{2}$

b) Probability that both slips having one odd number and one even  = $\frac{1}{2}$

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