Question

Two slits separated by 2.00 × 10–5 m are illuminated by light of wavelength 625 nm. If the screen is 6.00 m from the slits, what is the distance between the m = 0 and m = 1 bright fringes.

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Answer 1

$\underline{ \mathfrak{\huge{\boxed{\fcolorbox{purple}{orange}{\purple{Answer\::-}}}}}} \\ \\ \dagger \rm \: \red{Given} \begin{cases} \star \rm \: d = 2 \times {10}^{ - 5}m \\ \star \rm \: \lambda = 625 \times {10}^{ - 9} m \\ \star \rm \: D = 6 \: m \end{cases} \\ \\ \dagger \rm \: \red{To \: Find} \\ \\ \implies \rm \: distance \: between \: two \: bright \: fringes ... \\ \\ \dagger \rm \: \red{Formula} \\ \\ \implies \rm \: distance \: between \: two \: bright \: fringes \\ \rm \: is \: given \: by... \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \star \: \underline{ \boxed{ \bold{ \rm{ \purple{ \beta = \frac{ \lambda{D}}{d} }}}}} \: \star \\ \\ \dagger \rm \: \red{Calculation} \\ \\ \leadsto \rm \: \beta = \frac{625 \times {10}^{ - 9} \times 6}{2 \times {10}^{ - 5} } \\ \\ \leadsto \rm \: \beta = 1875 \times {10}^{ - 4} \: m \\ \\ \star \: \boxed{ \bold{ \rm{ \orange{ \beta = 18.75 \: cm}}}} \: \star$