two small circular parks of diameter 16 m and 12 m are to be replaced by bigger circular Park what would be the radius of the new Park if the new Park occupied the same space as the two small parks
Answers
Answered by
40
Area of park 1=pie *r^2=pie 8*8=64pie
Area of park 2=pie *6*6=36pie
Total area to form a new park =64pie+36pie=100pie
So
Pie*r^2=100pie
r^2=100
r=10
So radius of new park would be 10m
Area of park 2=pie *6*6=36pie
Total area to form a new park =64pie+36pie=100pie
So
Pie*r^2=100pie
r^2=100
r=10
So radius of new park would be 10m
Answered by
20
Area of circle is. π r square
so , for first , 3.14 x 16 x 16
803.84 m
fr 2nd, 3.14 x 12 x 12
452.16m
803.84+ 452.16 = 1256 m square
area of new bigger circle is 1256 m sq
3.14 x r square = 1256
r square = 708.16 m sq
and r = 26.61 m
so , for first , 3.14 x 16 x 16
803.84 m
fr 2nd, 3.14 x 12 x 12
452.16m
803.84+ 452.16 = 1256 m square
area of new bigger circle is 1256 m sq
3.14 x r square = 1256
r square = 708.16 m sq
and r = 26.61 m
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