[ two small conducting spheres each of mass 9 times 10^(-4)kg are suspended from the same point by non conducting strings of length 100 cm .they are given equal and similar charges until the strings are equally inclined at 45^ each to the vertical.the charge on each sphere is ......... coulomb.]
Answers
Answer:
Step-by-step explanation:
Mass of the sphere = 9×10−4kg (Given)
Length of the string = 100cm (Given)
Angle of inclination = 45° (Given)
Let Tcos45° = mg --- (1)
= Tsin45° = Kq²/(2l sin45)² --- (2)
Dividing equation (2) by (1)
= 1 = Kq² / (2l.1/√2)²
= q² = 2l²×m×g / K
= q² =2 × 9 × 10`−4×10/ 9×10`9
= q² =2×10`−12
q = 1.414×10`−6C
Thus, the charge on each sphere is 1.414×10`−6C.
Answer:
Step-by-step explanation:
Mass of the sphere = 9×10−4kg (Given)
Length of the string = 100cm (Given)
Angle of inclination = 45° (Given)
Let Tcos45° = mg --- (1)
= Tsin45° = Kq²/(2l sin45)² --- (2)
Dividing equation (2) by (1)
= 1 = Kq² / (2l.1/√2)²
= q² = 2l²×m×g / K
= q² =2 × 9 × 10`−4×10/ 9×10`9
= q² =2×10`−12
q = 1.414×10`−6C
Thus, the charge on each sphere is 1.414×10`−6C.