Question

Two small drops of mercury, each of
radius R, coalesce to form a single
large drop. The ratio of the total
surface energies before and after the
change is
1) 1:213
2) 23:1
4) 1:2
3) 2:1​

Answer 1

Answer:

3

Explanation:

2:1 because before coalesce they are two and after they are get 1

so the ratio is 2:1

Answer 2

Answer:

As initially

there was 2 drop that's why we are adding the surface energy of both drop