Two small equal charges 2×10 -8 C are placed at A and B; 6 cm from each other, one positive and the other negative. Find the force on a charge +1×10 -8 C placed at P, where P is 4 cm from the line AB, along the perpendicular bisector XP.
Answers
Answered by
0
Answer:
2×10-8=12 gggggggggggggggg
Similar questions