Question

Two small identical fierce x and y have charges + 12 microcoulomb and + 6 microcoulomb. If their separation is 0.5 metre, calculate the force between them when they are immersed in water (K=80)​

Answer 1

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you are welcome in my ans

we know that

F = kq1 *q2/r^2

k = 80

q1 = 12*10^-6c

q2 = 6*10^-6c

r = 0.5

F = 80*12*6*100*10^-12/5*5

F = 80* 12*24*10^-12

F = 960*24*10^-12

F = 2304*10^-11

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Hope it may helps you

Answer 2

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