Question

two small identical Spear carry charges of 16 microcoulomb and minus 4 microcoulomb find the force of electrostatic between them if they are separated by a distance of 1m in air

Answer 1

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Answer 2

Answer:

Two charges of 16 micro-coulomb and minus 4 micro-coulomb are separated by a distance of 1m apart in the air the electrostatic force between the charges is 0.57N

Explanation:

• The electrostatic force between two charges $q_{1} ,q_{2}$ separated by a distance $d$ is given by the formula

       $F=K\frac{q_{1} q_{2} }{r^{2} }$

       where the constant $K=9*10^{9}$

From the question, we have

the charges are $q_{1} =16*10^{-6}C$    and $q_{2} =-4*10^{-6}C$

the separation between them $r=1m$

therefore the force is

$F=\frac{9*10^{9}*16*10^{-6}*4*10^{-6} }{1^{2} }$

⇒ $F=0.57N$