Question

Two small iron particles each of mass 280mg are placed at a distance 10cm appart. lf 0.01% of the electrons of 1 particle are transfer to the other. Find electric force.




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Answer 1

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⏩No. Of molecules Iron=280×10^-3×na/56

Total electrons =26×280×10^-3×na/56

=78×10^-8

Total electrons transfer =0.01%×78×10^21

=7.8×10^18

Total charge electrons transfer =1.6×10^-19×7.8×10^18

=1.2 C

Coulomb force =9×10^9×(1.2)^2/(0.01)^2

=1.3×10^12 C

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