Question

Two small magnets are placed at points A and B on the frictionless horizontal table masses are 20 gram and 12 gram respectively the magnets are released and they move on the table due to mutual attraction when the first reaches a point A¹, its speed is count to be 3m/s. Find the speed of the other magnet and this magnet.​

Answer 1

Answer:

5 m/s

Explanation:

m1 × v1 = m2 × v2

20×10^-3 × 3 = 12×10^-3 × v2

v2 = (60×10^-3)/(12×10^-3)

v2 = 5 m/s

Answer 2

Answer:

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