Question

Two small spheres 18 cm apart have equal negative charges and repel each other with the force of 6 x 10-8 n. Find the total charge on both spheres.

Answer 1

Answer:

The charge on both the spheres will be $4.64\times 10^{-10}$ C

Explanation:

The force between two equal charges q separated by a distance r is given by

$F=k\frac{q^2}{r^2}$

where k is Coulomb's constant

$k=9\times 10^9\text{ N-m}^2\text{C}^{-2}$

Given r = 18 cm = $18\times 10^{-2}$ m

Force $F=6\times 10^{-8}$ N

Thus from the equation

$q^2=\frac{Fr^2}{k}$

$\implies q^2=\frac{6\times 10^{-8}\times (18\times 10^{-2})^2}{9\times 10^9}$

$\implies q^2=\frac{6\times 10^{-8}\times 18\times 18\times 10^{-4})}{9\times 10^9}$

$\implies q^2=6\times 18\times 2\times 10^{-21}$

$\implies q^2=21.6\times 10^{-20}$

$\implies q=\sqrt{21.6\times 10^{-20}}$

$\implies q=4.64\times 10^{-10}$ C

Therefore the charge on both the spheres will be $4.64\times 10^{-10}$ C

Hope this helps.

Answer 2

Answer:

Explanation:

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