Science, asked by Anonymous, 1 month ago

✒✒✒Two small spheres A and B of charges 18 esu and 8 esu respectively,
are placed at a distance 20 cm apart in air. At which point, the
electric field intensity will be zero ???✒✒✒

___Ok sis ___


report my this question and fast question please​

Answers

Answered by chouhansantoshkumars
1

Answer:

Initially 2nC and −8nC are separated by a distance d.

Electrostatic force acting between them initially F=

d

2

kq

1

q

2

∴ F=

d

2

(2)(8)k

=

d

2

16k

Now the two charges are allowed to touch each other, they share equal charges among themselves.

Total charge of the system Q=2−8=−6nC

Thus new charge on each sphere q

1

=q

2

=−3nC

Let the new distance between them be d

.

Thus force acting between them F

=

(d

)

2

kq

1

q

2

∴ F

=

(d

)

2

k(−3)(−3)

=

(d

)

2

9k

But F

=F

(d

)

2

9k

=

d

2

16k

Or (d

)

2

=

16

9

d

2

⟹ d

=

4

3d

Answered by kumariayushi6157
2

Answer:

hello harsh!!!!!!!!!!!

Similar questions