Question

Two small spheres are kept 10m apart in air and they contain 5C and 10C charges. Find the effective force between them. Please help me with this sum please I request all of you...​

Answer 1

GiveN :

• Charge of 1st sphere $\rm{Q_1 \: = \: 5 \: C}$
• Charge of 2nd charge $\rm{Q_2 \: = \: 10 \: C}$
• Distance Between Charges $\rm{d \: = \: 10 \: m}$

To FinD :

• Electrostatic Force between charges

SolutioN :

Use Coulomb's inverse square law :

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$\implies \boxed{\rm{F = \dfrac{1}{4 \pi \epsilon_0} \dfrac{Q_1 Q_2}{d^2}}}$

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Putting Values

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$\implies \rm{F = (9 \times 10^9) \bigg( \dfrac{5 \times 10}{10^2}\bigg) }$

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$\implies \rm{F = (9 \times 10^9) \times \bigg( \dfrac{5 \times 10}{10 \times 10} \bigg)}$

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$\implies \rm{F = 9 \times 10^9 \times \dfrac{5}{10}}$

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$\implies \rm{F = 9 \times 10^9 \times 0.5}$

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$\implies \rm{F = 4.5 \times 10^9}$

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$\underline{\rm{\therefore \:Electrostatic \: force \: between \: spheres \: is \: 4.5 \:\times \: 10^9 \: N}}$

Answer 2

GiveN :

1 =5C

2 =10C

Distance Between Charges

d=10m

To FinD :

Electrostatic Force between charges

SolutioN :

Use Coulomb's inverse square law :

ㅤ⟹ F= 4πϵ 01d 2

Putting Values

⟹F=(9×10 9 )( 10 ×25×10)

⟹F=(9×10 9 )×( 10×105×10 )

⟹F=9×10 9 × 105

⟹F=9×109×0.5

⟹F=4.5×10 9

∴Electrostaticforcebetweenspheresis4.5×10 9 N