Two smooth spheres each of the radius 5cm and weight W rest one on other inside a fixed smooth cylinder of radius 8cm the reactions between spheres and vertical side of cylinder are
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see diagram.
First get the lengths of various sides. Then the angle of the line joining the two centers of spheres.
F1, F2, F3 and F4 are contact forces of actions and reactions.
W = mg given.
Tan Ф = 4/3. SinФ = 4/5. CosФ = 3/5.
Since the system is in static equilibrium, we balance the horizontal and vertical forces.
F1 = F3 * CosФ = 0.60 F3
W = m g = F3 SinФ = 0.80 F3
=> F3 = 1.25 W. => F1 = 0.750 W.
W + F3 SinФ = F4
F4 = W + W = 2 W
F2 = F3 CosФ = F1 = 0.750 W
First get the lengths of various sides. Then the angle of the line joining the two centers of spheres.
F1, F2, F3 and F4 are contact forces of actions and reactions.
W = mg given.
Tan Ф = 4/3. SinФ = 4/5. CosФ = 3/5.
Since the system is in static equilibrium, we balance the horizontal and vertical forces.
F1 = F3 * CosФ = 0.60 F3
W = m g = F3 SinФ = 0.80 F3
=> F3 = 1.25 W. => F1 = 0.750 W.
W + F3 SinФ = F4
F4 = W + W = 2 W
F2 = F3 CosФ = F1 = 0.750 W
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kvnmurty:
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see thee answer in attachment hope it will help thanks
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