Physics, asked by spranav1800, 9 months ago

Two soap bubbles of radii 2 mm2 mm and 4 mm4 mm are brought in contact. If the surface tension of liquid is 7102nm17102nm1. Then the radius of the common surface is :

Answers

Answered by RvChaudharY50
47

Answer:

shortcut :---

if r is double in this case , than

radius of common surface will be alwz equal to :-

r = (yx/y-x) where y = 2x

putting values we get ,

r = 4*2/(4-2) = 4 (Ans.)

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