Question

Two soap bubbles of radii r1 and r2 equal to 4cm and 5cm are touching each other over a common surface s1s2. Its radius will be?

Answer 1

The options for this question are missing, here are the missing options:

1) 20 cm

2) 1 cm

3) 1.25 cm

3) √41 cm

Answer:

4T / R = GT/R₁ - 4 T/ R₂

= 1/R = 1/4 - 1/5

= R = 20 cm

20 cm is the final answer for this question.

If there is any confusion please leave a comment below.

Answer 2

Answer:

The radius of the required bubble = 20 cm

Step-by-step explanation:

Let the required radius be R cm

Radius of the first soap bubble = 4 cm

Radius of the second soap bubble = 5 cm

Since, the two soap bubbles are touching each other over a common surface.

So, the required Radius R can be find by using the following relation :

$\frac{1}{R}=\frac{1}{R_1}-\frac{1}{R_2}\\\\\implies\frac{1}{R}=\frac{1}{4}-\frac{1}{5}\\\\\implies\frac{1}{R}=\frac{5-4}{20}\\\\\implies\frac{1}{R}=\frac{1}{20}$

⇒ R = 20 cm

Hence, The radius of the required bubble = 20 cm