Question

two soaps A and B are given. Dimension of B are 50% more than each dimensions ofA. Soap content of B as compared to A is​

Answer 1

Answer:

ANSWER

Let each dimension of soap A =x

We assume soap to be a cube

So each dimesion of soap B =1.5x

So, soap content in A =x

3

Soap content in B=(1.5x)

3

=3.375x

3

⇒ Soap content of B =3.375× Soap content of A