Question

Two solid cylinders of radii 4 cm and 5cm and length 6 cm and 4 cm respectively are recast into cylindrical disc of thickness1 cm. The radius of the disc is

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

13.997 cm

Step-by-step explanation:

We first need to get the total volume of the two shapes.

Volume of a cylinder = pie × r^2 × h

We substitute this as follows :

Pie = 3.142

The first cylinder = 3.142 × 4 × 4 × 6 = 301.362 cubic centimeters.

The second cylinder = 3.142 × 5 × 5 × 4 = 314.2 cubic centimeters.

Total volume = 314. 2 + 301.362 = 615.562 cubic centimeters.

The thickness of the disk gives the height.

Since volume of the disk is equal to the total volume of the cylinders we equate this to the volume of the disk.

615.562 = 3.142 × 1 × r^2

r^2 = 195.914

r = square root of 195.914

r = 13.997 cm

Rounding off :

r = 14 cm