two solids A and B float in water.It is observed that A floats with half of its volume immersed and B floats with 2/3 of its volume immersed.What is the ratio of their densities?
Answers
Answered by
355
Take equal volume of A and B, say V.
Weight of A = Weight of V/2 volume of water.
Similarly, weight of B = Weight of 2V/3 volume of water.
As density is weight per unit volume, the required ratio will be
D(A)/D(B)=(V/2)/(2V/3) =3/4
Thus, density of A : density of B = 3:4
[Answer]
For, any clarification you may comment please!
Weight of A = Weight of V/2 volume of water.
Similarly, weight of B = Weight of 2V/3 volume of water.
As density is weight per unit volume, the required ratio will be
D(A)/D(B)=(V/2)/(2V/3) =3/4
Thus, density of A : density of B = 3:4
[Answer]
For, any clarification you may comment please!
Answered by
36
Answer:answer is 4:3
Explanation:
As density =mass/volume
Density is inversely proportional to volume
Given, volume of A=1/2
Volume of B=2/3
Hence, d(A)/d(B)=v(B)/v(A)
=2/3/1/2
=2/3×2/1
=4/3
=4:3
Similar questions