Two solids A and B float in water it is observed that A floats with 1/2 of its body immersed in water and B floats with 1/4 of its volume above water level the ratio of density of a to that of B is
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Explanation:
Let the density of A be a and the density of B be b
Given that,
From Archimedes principle,
V(total volume of body A )*a*g=(volume of body A inside water) *density*g
(Volume of body inside water/total volume of body A) =(a/density of water)=1/2------>1
Similarly
(b/density of water)=3/4----->2
Divide 1 by 2
We get
a/b =2/3
The ratio is 2:3
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