two solids A and B float in water it is observed that ice floats with half of its volume immersed and D floats with 2 by 3 of its volume immersed the ratio of their densities is
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Take equal volume of A and B, say V.
Weight of A = Weight of V/2 volume of water.
Similarly, weight of B = Weight of 2V/3 volume of water.
As density is weight per unit volume, the required ratio will be
D(A)/D(B)=(V/2)/(2V/3) =3/4
Thus, density of A : density of B = 3:4
Weight of A = Weight of V/2 volume of water.
Similarly, weight of B = Weight of 2V/3 volume of water.
As density is weight per unit volume, the required ratio will be
D(A)/D(B)=(V/2)/(2V/3) =3/4
Thus, density of A : density of B = 3:4
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