Two solids of right cylindrical shape are 49 cm and 35 cm high and their base
diameters are 16 cm, 14 cm respectively. Both are melted and moulded into a
single cylinder, 56 cm high. Find its base diameter.
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Answer:
1 cylinder = height 49 and base 35
2 cylinder = height 49 and base 35
3 cylinder = 56 hight
But 35 is a diameter therefore we will take 35/2
Now formula for cylinder = πr² × l
Therefore ( 22/7 × 35/2 × 49 ) + ( 22/7 × 35/2 × 49 ) = πr²( 56 )
Solve these you will get your answer ✌
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