Question

Two solids of right cylindrical shape are 49 cm and 35 cm high and their base diameters are 16 cm, 14 cm respectively. Both are melted and moulded into a single cylinder, 56 cm high. Find its base diameter. ​

Answer 1

Answer:

According to question

Radius of first cylinder   R1 = 16/2 = 8 Cm

Height of first cylinder     H1 = 49 Cm

So Volume     V1 = pi R1^2 H1

                            = pi * 64 * 49

Similarly

 Radius of second cylinder    R2 = 14/2 = 7 Cm

Also  Height                           H2 = 35 Cm

So  Volume     V2 = pi R2^2 H2

                              = pi * 49 * 35

When Moulded    Total volume    V = V1 + V2

                                                    V = pi [ 64 * 49 + 49 * 35 ]

Height of New cylinder   H = 56 Cm

Let radius be R

So      V = pi R^2 H

          Pi [ 64 * 49 + 49 * 35 ] = pi R^2 * 56

             R = 9.30 Cm

Thus Diameter = 18.60 Cm

Answer 2

Answer:

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Explanation:

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