Question

Two solids of right cylindrical shape are 49 cm and 35 cm high and their base diameters are 16 cm, 14 cm respectively. Both are melted and moulded into a single cylinder, 56 cm high. Find its base diameter. ​

Answer 1

Refer from the attachment

hope it helps...

Answer 2

Solution :-

Let us assume that, the radius of single cylinder is r cm .

So,

→ Volume of single cylinder = Sum of volume of 2 solid cylinders

putting given values we get,

→ πr² * 56 = π(8)² * 49 + π(7)² * 35

cancel π from both sides ,

→ r² * 56 = 49(64 + 35)

→ r² * 8 = 7 * 99

→ r² = (693/8)

→ r ≈ 9.3 cm .

therefore,

→ Diameter of base = 2r = 2 * 9.3 = 18.6 cm .

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