Two solids of right cylindrical shape are 49 cm and 35cm high and their base diameters are 16cm and 14cm respectively . both are melted and moulded into a single cylinder 56cm high. find it's base diameter
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1st cylinder :
Height = 49 cm
Diameter = 16cm
Radius = 8 cm
Volume = 22/7 ×8 ×8 ×49 cm^3
2nd cylinder :
Height = 35 cm
Diameter = 14 cm
Radius = 7 cm
Volume = 22/7 ×7 ×7 ×35 cm^3
Single / Big cylinder :
Radius =r
Height = 56 cm
Volume = 22/7 ×r ×r ×56 cm^3
A.T.Q :
Volume of the big cylinder = Volume of 1st cylinder + Volume of 2nd cylinder
22/7 ×r ×r ×56 = 22/ 7 ×8 ×8 ×49 + 22/7 ×7×7 ×35
22/7 ×r×r×56 = 22/7( 64 ×49 + 49 ×35)
r ×r ×56 = 49 ( 64 + 35)
r^2 = ( 64 + 35) 49 /56
r ^2 = 99×7/ 8
r ^2 = 693 /8 cm
( Hey friend I have tried to satisfy you with my answer but it seems like your question is mistake or the values are. It would be easier for me to give you the correct answer if you send me the answer. Hope it will help you.)
Height = 49 cm
Diameter = 16cm
Radius = 8 cm
Volume = 22/7 ×8 ×8 ×49 cm^3
2nd cylinder :
Height = 35 cm
Diameter = 14 cm
Radius = 7 cm
Volume = 22/7 ×7 ×7 ×35 cm^3
Single / Big cylinder :
Radius =r
Height = 56 cm
Volume = 22/7 ×r ×r ×56 cm^3
A.T.Q :
Volume of the big cylinder = Volume of 1st cylinder + Volume of 2nd cylinder
22/7 ×r ×r ×56 = 22/ 7 ×8 ×8 ×49 + 22/7 ×7×7 ×35
22/7 ×r×r×56 = 22/7( 64 ×49 + 49 ×35)
r ×r ×56 = 49 ( 64 + 35)
r^2 = ( 64 + 35) 49 /56
r ^2 = 99×7/ 8
r ^2 = 693 /8 cm
( Hey friend I have tried to satisfy you with my answer but it seems like your question is mistake or the values are. It would be easier for me to give you the correct answer if you send me the answer. Hope it will help you.)
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