Question

Two solutions A and B when taken separately in the same conductivity cell had a resistance of 40ohm and 60 respectively.If equal volumes of both the solutions are mixed then the resistance of the mixture will be(Assume that there is no increase in the degree of dissociation of A and B on mixing)

Answer 1

Hey dear,

● Answer-
Option (B) k = 24 ohm

● Explanation-
# Given-
k1 = 40 ohm
K2 = 60 ohm
V1 = V2

# Solution-
As same volumes of solution are added, resistance of combined soln-
k = k1.k2 / (k1+k2)
k = 40×60 / (40+60)
k = 2400 / 100
k = 24 ohm

Therefore, resistance of the mixture is 24 ohm.

Hope it helps...

Answer 2

"Given, two solutions A and B having same conductivity

Solution A resistance k1 = 40 ohm

solution B resistance K2 = 60 ohm

If the volume of the two solutions A and B are equal then V1 = V2.

If both are mixed then the resistance of the mixture is to be calculated.

Let us consider that there is no increase in the degree of dissociation of the solution A and B while on mixing.

As same volume of solution A and B are added, then the resistance of combined solution is given as,

k = k1.k2 / (k1+k2)

k = 40×60 / (40+60)

k = 2400 / 100

k = 24 ohm

Therefore, resistance of the mixture is 24 ohm."