Question

Two solutions of 92% and 98% purity respectively , are mixed together resulting in a mixture of 95% purity. What is the ratio of the quantity of the first solution to the quantity of the second solution in the 95 % purity mixture ? A. 1:1 B. 1:2 c. 1:3 d. 2:3​

Answer 1

Answer:

Where allegation method as mentioned below looks like Awesome and Impressive method, in complete agreement with it I prefer to teach students to learn to make the equation which is strongest way to solve such question of any difficulty.

Let, 90% solution has quantity A

Let, 97% solution has quantity B

So total Solution will be A+B = 21 (Given)

The equation is formed as mentioned here

Concentrate of A + Concentrate of B = Concentrate of (A+B)

i.e. (90/100)*A + (97/100)*B = (94/100)*(A+B)

i.e. 4A = 3B

Also, A+B = 21

i.e. A+(4A/3) = 21

i.e. A=9

Answer 2

Answer:

A) 1:1

Explanation:

There are two solution A and B

Let the purity of the solutions be as follow

A = 92%

B = 98%

The solution mixture is 95%

Percentage of

A + B = solution mixture

$\frac{92}{100}$ + $\frac{98}{100}$ = $\frac{95}{100}$(ratio)

therefore the ratio is

$\frac{92}{95}$ +$\frac{98}{95}$ = ratio

0.96 +  1.03 = ratio

1 + 1 = ratio

therefore the ratio is 1:1