Question

Two solutions of a non-electrolyte are mixed in the following manner.480 ml of 1.5 M first solution+520 ml of 1.2 M second solution. what is the molarity of the final solution?

Answer 1

Answer: The molarity of the final solution is 1.34 M

Explanation:

Formula used

$C_1V_1+C_2V_2=C_3V_3$

where,

$C_1$ and $C_2$ are the concentrations

$C_3$ is the concentration of resulting solution = ?

$V_1$ and $V_2$ are the volume

$V_3$ is the volume of resulting solution = 480+520 = 1000 ml

Now put all the given values in the above formula, we get the concentration of resulting solution.

$(1.5\times 480)+(1.2\times 520)=C_3\times 1000$

$C_3=1.34M$

The concentration of the resulting solution = 1.34 M

Answer 2

Answer:

1.344 M is the correct answer ..

Explanation:

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