Question

Two solutions of alcohol A and B were mixed to obtain 20 litres of new solution C. Before they were mixed, the first solution A contained 1.6 litres of alcohol
while the second solution B contained 1.2 litres of alcohol. Before mixing if the percentage of alcohol in the first solution A was twice that in the second B,
what was the volume of the first solution A before mixing?
​

Answer 1

Solution :-

given that,

→ In A be the volume of alcohol = 1.6 litres .

→ In B be the volume of alcohol = 1.2 litres .

and,

→ A + B = 20 litres ----------- Eqn.(1)

A/q,

→ % of alcohol in A = 2 * % of alcohol in B .

→ (1.6/A) = 2(1.2/B)

→ 1.6/A = 2.4/B

→ A/B = 1.6/2.4

→ A/B = 2/3

→ B = (3A/2)

putting value of B in Eqn.(1),

→ A + (3A/2) = 20

→ (2A + 3A)/2 = 20

→ 5A = 20 * 2

→ 5A = 40

→ A = 8 litres (Ans.)

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