Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the solution is made up of a 20% acid solution. The remaining three-quarters is made up of a solution of unknown concentration, c. Which equation can be used to determine c, the unknown concentration? 30c + 10(0.2) = 40(0.32) (c) + (0.2) = 40(0.32) (c)( (0.2)) = 40(0.32) 30(c)(10(0.2)) = 40(0.32)
Answers
Given : Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid.
One-quarter of the solution is made up of a 20% acid solution
The remaining three-quarters is made up of a solution of unknown concentration, c
To Find : Which equation can be used to determine c, the unknown concentration?
30c + 10(0.2) = 40(0.32)
(c) + (0.2) = 40(0.32)
(c)( (0.2)) = 40(0.32)
30(c)(10(0.2)) = 40(0.32)
Solution:
40 mL of a solution with 32% acid
one Quarter = 10 ml with 20% acid.
three Quarter = 30 ml with unknown c
Equating acid
10( 20 /100) + 30(c) = 40(32/100)
=> 10(0.2) + 30c = 40(0.32)
=> 30c + 10(0.2) = 40(0.32)
30c + 10(0.2) = 40(0.32) is the correct Equation which can be used to determine c,
on solving c = 0.36 hence 36% concentration
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