Question

Two solutions of HCl 1) 2M 2L HCl and 2) 3M 1L are available. You have been asked to prepare 2.8M HCl by mixing above solutions, without using water. What is maximum volume of 2.8M HCl that you can prepare?​

Answer 1

10L is the maximum volume of 2.8M HCl that can be prepared.

Explanation:

As we know,

$M_{1} V_{1} + M_{2} V_{2} = M_{3} V_{3}$

(3 * x) + (2 * 2) = 2.8(2 + x)

3x + 4 = 5.6 + 2.8x

0.2x = 5.6 - 4

0.2x = 1.6

x = 1.6/0.2

x = 8

∵ Maximum volume = 2 + x

= 2 + 8

= 10L

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