Question

Two solutions of milk and water are combined
in the ratio of volumes 2:3. The
resultant solution is a 40% milk solution Find
the concentration of the first solution if the
concentration of the second is 60%​

Answer 1

Answer:

Let the concentration of the milk in first solution be x.

As per the question then x% and 60% give an end result of 40% solution.

So 20/(40-x) = 2/3

Solving we get x as 10

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Answer 2

Answer:$10$

Step-by-step explanation:

Let x be the concentration of  milk in the initial solution.

Depending on the question, then $x$% and $60%$% give the final result a

$40$% solution.

So$20 / (40-x) = 2/3$

Solving we get $x$ is $10$

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