Math, asked by anshuwadhwa, 6 months ago

Two solutions of the linear equation 2x - 3y = -11 are *



a) (-1, 3) and (4, 1)

b) (-1, 3) and (2, -5)

c) (2, 5) and (1, 3)

d) (2, 5) and (-1, 3)

Answers

Answered by Anonymous
3

Answer:

d ) ( 2, 5 ) and ( - 1, 3 )

Step-by-step explanation:

d ) ( 2, 5 ) and ( - 1, 3 )

2x - 3y = - 11

Substitute ( 2, 5 ) is the equation 2x - 3y = - 11,

2 ( 2 ) - 3 ( 5 ) = - 11

4 - 15 = - 11

- 11 = - 11

Therefore, ( 2, 5 ) is a solution of the equation 2x - 3y = - 11.

Substitute ( -1, 3 ) is the equation 2x - 3y = - 11,

2 ( - 1 ) - 3 ( 3 ) = - 11

- 2 - 9 = - 11

- 11 = - 11

Therefore, ( -1, 3 ) is a solution of the equation 2x - 3y = - 11

Therefore, both ( 2, 5 ) and ( - 1, 3 ) is a solution of the equation 2x - 3y = - 11.

( For this kind of sum, you can find the answer by substituting the option given and find the answer )

Answered by DhiruRiluloveyou
1

Answer:

d) (2,5) and (-1,3)

Step-by-step explanation:

hope it help you

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