Question

two solutions of volume 600ml and 500ml having normalities 1.5N and 2.6N are mixed. find the resultant normality of the solution.

Answer 1

Answer:-

Given:-

Normality of first solution (N₁) = 1.5 N

Volume of first solution (V₁) = 600 ml = 600/1000 L = 0.6 L [∵ 1 ml = 1/1000 L ]

Normality of second solution (N₂) = 2.6 N

Volume of second solution (V₂) = 500/1000 = 0.5 L

We know that, when two different solutions of normalities N₁ & N₂ and volumes V₁ & V₂ are mixed , then the normality of the resulting solution will be:

$\sf \: N = \dfrac{N_1V_1 +N_2V_2 }{V_1 + V_2}$

Hence,

Normality of the resulting solution (N) = [ (1.5)(0.6) + (2.6)(0.5) ] / (0.6 + 0.5)

⟹ N = (0.9 + 1.3) / 1.1

⟹ N = 2.2/1.1

⟹ N = 2 Normal

∴ Normality of the resulting solution is 2 N.