two soun waves of wavelength 17/22 m and 170/222m bear at 4 per second in air when they arrive at a point simultaneously the speed of sound in air is
Answers
Given info : Two sound waves of wavelength 17/22 m and 170/222 m bear at 4 per second in air when they arrive at a point simultaneously.
To find : The speed of sound in air is ...
solution : beat is change in frequency of two wave in a medium.
so, beat = |v₁ - v₂| = |v/λ₁ - v/λ₂|
because we know, frequency = speed of wave/wavelength so, v₁ = v/λ₁ and v₂ = v/λ₂
here beat = 4 per second
and λ₁ = 170/222 m and λ₂ = 17/22 m
so, 4 = v|1/(170/222) - 1/(17/22)|
⇒4 = v|222/170 - 22/17|
⇒4 = v|2/170|
⇒v = 170 × 4/2 = 340 m/s
Therefore the speed of sound in air is 340 m/s.
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