Question

Two sound sources are moving in opposite directions with velocity V1 and V2 (v1>v2).Both are moving away from a stationary observer. the frequency fo both the sources is 900Hz.What is the value of V1-V2 so that the beat frequency observed by the observers is 6Hz.​

Answer 1

Explanation:

1 =900( 300+v 1300)

⟹f 1 =900(1+ 300v1 )

−1

⟹f 1 =900−3v1

Similarly

f 2 =900−3v2

So,

f 1 −f 2

=63(v 1 −v 2 )=6

⟹v 1 −v 2 =2 ms −1