Two sound waves emerging from a source reach a point simultaneously along two paths. when the path difference is 12 cm or 36 cm, then there is silence at the point. Find the frequency of the source if the speed of sound in air is 330.
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Answered by
69
Concept :
Path difference between consecutive: Max-Max or Min-Min = wavelength(a)
And between Max-Min or Min-Max = a/2
Silence point/Destructive/Min
It's a case of consecutive silent point ie Min-Min
So, Wavelength(a) = 60-36= 24cm =0.24 m
V = na
330 =n*0.24
1375 Hz =n
#I have changed notation of wavelength as can't type lamda here.. So, I'm using 'a' instead of lamda to denote wavelength.
this may help you
Path difference between consecutive: Max-Max or Min-Min = wavelength(a)
And between Max-Min or Min-Max = a/2
Silence point/Destructive/Min
It's a case of consecutive silent point ie Min-Min
So, Wavelength(a) = 60-36= 24cm =0.24 m
V = na
330 =n*0.24
1375 Hz =n
#I have changed notation of wavelength as can't type lamda here.. So, I'm using 'a' instead of lamda to denote wavelength.
this may help you
Answered by
6
Explanation:
here by taking diff and by applying formula we can get ans
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