Two sound waves having a phase difference of60°,have a path difference equal to
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We know the relation between path difference , phase difference and wavelength of wave is given by
∆Ф = 2π/λ ∆x
Here ∆Φ is phase difference , ∆x is path difference and λ is wavelength of wave.
Given, ∆Φ = 60° = 60° × π/180° = π/3 rad
Wavelength is not mentioned so, assumed wavelength is λ
Now, π/3 = 2π/λ ∆x
∆x = λ/6
Hence path difference is λ/6
∆Ф = 2π/λ ∆x
Here ∆Φ is phase difference , ∆x is path difference and λ is wavelength of wave.
Given, ∆Φ = 60° = 60° × π/180° = π/3 rad
Wavelength is not mentioned so, assumed wavelength is λ
Now, π/3 = 2π/λ ∆x
∆x = λ/6
Hence path difference is λ/6
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