Question

Two sound waves having wavelengths 50 cm & 50.5 cm respectively produce 6 beats per second
in a gaseous medium. The velocity of second in that medium is
A 301m/s
B 302m/s
C 300m/s
D 303m/s​

Answer 1

Answer:

D

Explanation:

First velocity of 50cm wavelength and frequency 6 is 300m/s

Sencond velocity of 50.5cm and frequency 6 is 303m/s

By the formula-

v=lamda×new

Answer 2

Answer:

The velocity of sound in the given medium is option D) 303 m/s

Explaination:

Number of beats produced b= f1-f2

The number of beats per second is given by the difference between their frequencies.

⇒b= (v÷λ1)-(v-λ2)=v((1÷λ1)-(1-λ2))

Where b is the number of beats per second, v is the velocity of sound, λ is the wavelength of the respective waves.

⇒6 = v((1÷0.50)-(1÷0.505))

⇒v = 303 m/s

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