Two sound waves having wavelengths of 87 cm and 88.5cm respectively, when superimposed, produce 10 beats per second. Find the velocity of sound (Ans : 513.3 m/s)
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wavelength of first sound , = 87cm = 0.87m
wavelength of 2nd sound, = 88.5cm = 0.885m
we know,
so, frequency is inversely proportional to wavelength.
so, frequency of first ever is higher than frequency of 2nd wave.
given, number of beats per second = 10
so,
or,
or, v(1/0.87 - 1/885) = 10
after solving it we get, v = 513.3 m/a
wavelength of 2nd sound, = 88.5cm = 0.885m
we know,
so, frequency is inversely proportional to wavelength.
so, frequency of first ever is higher than frequency of 2nd wave.
given, number of beats per second = 10
so,
or,
or, v(1/0.87 - 1/885) = 10
after solving it we get, v = 513.3 m/a
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Answer:
Two sound waves having wavelengths of 87 cm and 88.5cm respectively, when superimposed, produce 10 beats per second. Find the velocity of sound (Ans : 513.3 m/s)
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wavelength of first sound ,
= 87cm = 0.87m
\lambda_1
wavelength of 2nd sound,
= 88.5cm = 0.885m
\lambda_2
we know,
v=n\lambda
so, frequency is inversely proportional to wavelength.
so, frequency of first ever is higher than frequency of 2nd wave.
given, number of beats per second = 10
so,
n_2-n_1=10
or,
\frac{v}{\lambda_1}-\frac{v}{\lambda_2}=10
or, v(1/0.87 - 1/885) = 10
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