Two sound waves having wavelengths of 87 cm and 88.5cm respectively, when superimposed, produce 10 beats per second. Find the velocity of sound (Ans : 513.3 m/s)
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Answered by
33
Given :
λ1 = 87 cm = 0.87 m,
λ2 = 88.5 cm = 0.885 m
Beat frequency, N = 10 beats per second
: v1 = n1/ λ1 and v2 = n2/ λ2
∴ n1 = v /λ1 and n2 = v/ λ2
∵ λ2 > λ1 hence n1 > n2
∴ N = n1 – n2 = v/ λ1 – v /λ2
= v[ 1/0.87 – 1/0.885]
10=v[[ 1/0.87 – 1/0.885]
10=v[0.885-0.87/0.87x0.885]
V=10xx0.87x0.885/0.015
V=513.3m/s
∴Veloccity of sound=513.3m/s
Answered by
1
Answer:
above answer is correct
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