Question

Two sources of same intensity interfere at a point and produced resultant II. When one source is removed, the intensity at that point will be

Answer 1

The intensity at point P would be Io/4.

Explanation:

Phase difference = 2π /3

If intensity at central fringe is Io, then intensity at point p where phase difference is Φ is given by.

I = Iocos^2Φ

=> I = Io (cos2π /3)^2 = Io (-cos π /3)^2

   I = Io (-1/2)^2 = Io/4

Thus the intensity at point P would be Io/4.

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