Question

Two sphere charged with equal but opposite charges experiences a force of 25x10^5N when they are placed 2cm apart in a medium of relative permittivity 5. determine the charge of each sphere.?

Answer 1

Answer:

q=2.4x10-5a

Explanation:

Answer 2

Since q1 and q2 have equal but  contrary charges, we can conclude that each sphere has a charge of ±8.99x10- 6 C which is given by Coulomb's law.  

The electrostatic force between two charged spheres is given by Coulomb's law.

F = ( 1/ 4πε) *( q1*q2)/ r2  

Where F is the force,  

q1 and q2 are the charges on the spheres,  

r is the distance between the centers of the spheres,  

and ε is the permittivity of the medium.  

In this problem,  

We know that the spheres have equal but  contrary charges, so q1 = - q2.

We also know that,

The force between the spheres is 25x105 N  

when they're 2 cm (or0.02 m) piecemeal in a medium with relative permittivity of 5.  

Thus, we can write x105 N = ( 1/4πε) *( q1*q2)/$(0.02 m)2$

Substituting q1 = - q2 and ε =  ε0*εr

(where ε0 is the vacuum permittivity, which is a constant equal to 8.85x10- 12 F/ m),  

we get  25x105 N = ( 1/ 4πε0εr) *( q1) 2/(0.02 m) 2  working for q1,  

we get  q1 =  ± √(( 25x105 N) *( 4πε0εr) *(0.02 m) 2)  q1 =  ±8.99x10- 6 C  

Since q1 and q2 have equal but  contrary charges, we can conclude that each sphere has a charge of ±8.99x10- 6 C which is given by Coulomb's law.  

For similar questions on Coulomb's law,  

https//brainly.in/ question/ 5438370  

#SPJ2