Question

two sphere of radii in ratio 1:2 and densities in ratio2:1 and of same specific heat ,are heated to same temperature and left in the same surrounding. the ratio of falling temperature will be ratio.

Answer 1

Hey buddy,

● Answer-
1:1

● Explaination-
# Given-
r1/r2 = 1/2
d1/d2 = 2/1

# Solution-
Rate of cooling is given by -
dθ/dt = (m × c) / (A × T)
dθ/dt = (V×d × c) / (A × T)
dθ/dt = (4/3)πr^3d × c / (πr^2 × T)
dθ/dt = (4/3)rdc / T

For both spheres, c & T are constant, therefore-
(dθ1/dt) / (dθ2/dt) = (4r1d1c/3T) / (4r2d2c/3T)
(dθ1/dt) / (dθ2/dt) = r1d1 / r2d2
(dθ1/dt) / (dθ2/dt) = (r1/r2)(d1/d2)
(dθ1/dt) / (dθ2/dt) = 1/2 × 2
(dθ1/dt) / (dθ2/dt) = 1

Ratio of temp. cooling for spheres is 1:1 .


Hope this helps...

Answer 2

Answer:

the answer for your question is 1:16

I hope this helps you to find out your question