Question

Two sphere of same radius R have their density in the ratio 8:1 and ratio of specific heat is 1:4 if the radiation rate of fall of temperature are same then find the ratio of loss of heat

Answer 1

Explanation:

Correct option is

A2( dtdQ) 1 =m

1 s 1 ( dtdT ) 1( dtdQ )

2

=m

2

s

2

(

dt

dT

)

2

Given,

(

dt

dT

)

1

=(

dt

dT

)

2

∴

(

dt

dQ

)

2

(

dt

dQ

)

1

=

m

2

s

2

m

1

s

1

=

m

2

m

1

×

s

2

s

1

=

d

2

d

1

×

s

2

s

1

=

1

8

×

4

1

=

1

2