Question

Two sphere of same radius R have their density in the ratio 8:1 and ratio of specific heat is 1:4 if the radiation rate of fall of temperature are same then find the ratio of loss of heat

Answer 1

Explanation:

Correct option is

A

2

(dtdQ)1=m1s1(dtdT)1

(dtdQ)2=m2s2(dtdT)2

Given,

(dtdT)1=(dtdT)2

∴(dtdQ)2(dtdQ)1=m2s2m1s1=m2m1×s2