Question

Two spheres a and b of masses m1 and m2 respectively collide. A is at rest initially and b is moving with velocity v along x-axis. After collision b has a velocity 2 v in a direction perpendicular to the original direction. The mass a moves after collision in the direction

Answer 1

Solution :-

We will use two dimensional moment conversation.
let as assume the direction B move initially is positive x direction

so we can write,

m1×0+m2×V= m2×0+m1×VxA as B is moving y direction only a after collision

so

VxA = m2/m2 V towards positive direction

and similarly m1 ×0+ m2×0 = m1 × VyA +m2×V/2

VyA = - m2v/ 2m1

VyA/VxA = - 1/2 = tanθ

massA will move than tan^-1 (-0.5) = 26.5° with positive x axis.

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@GauravSaxena01

Answer 2

plz refer to the attachment...

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